i just need short but decent answer/explanation. Thanks for all the help. Two id

Question

i just need short but decent answer/explanation. Thanks for all the help.

Two identical bulbs and a capacitor are connected to an ideal battery as shown. The capacitor is initially unchanged. Just after the switch is closed: what is the potential difference across bulb A, across bulb B, across the capacitor C, and across the battery? Explain. rank the currents i_A, i_B, i_C, and i_bat. Explain your reasoning. A long time after the switch is closed: rank the currents i_A, i_B, i_C, and i_bat. Explain your reasoning. what is the potential difference across bulb A, bulb B, the capacitor C, and the battery? Explain. Summarize your results by describing the behavior of bulb A and of bulb B from just after the switch is closed until a long time later

Explanation / Answer

2)

a. just after the switch is closed

capacitor will be short circuited

potential difference across bulb A = Vbat

potential difference across bulb B = 0 V

current in bulb B will be zero

as capacitor , battery and bulb A are in series

iA = iC = ibat > iB

b.

a long time after

the capacitor will be open circuited

there will be no current in capacitor C

iA = iB = ibat < iC

potential difference across A = Vbat/2

potential difference across B = Vbat/2

potential difference across capacitor = Vbat/2

potential difference across battery = Vbat

c)

as the potential across the bulb A is decreasing from Vbat to Vbat/2 , bulb A will become dimmer with time.

initially ,current in bulb B is zero and potential becomes Vbat/2 after a long time.bulb B becomes brighter with time

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