acids and wCIn ate hydrolytic reaction of sodium acetate. a Calculate the hydrol

Question

acids and wCIn ate hydrolytic reaction of sodium acetate. a Calculate the hydrolytic constant Kh. . of sodium acetate Kw=1.01x10-14 and Ka=1.75x10-5- 4 Find the degree of hydrolysis for a 0.02 molar solution of sodium at 25 , if 5°C. A and B are placed in a reaction vessel at zero time, where CAo - CBo. The following reactions occur at constant volume where Mis the desired product. If both reactions are second-order, derive an expression for the selectivity of M with respect to D in terms of the total.con- version of B. e overall rate expression of reaction 2NO+2H2 N2+2H20- (14%)

Explanation / Answer

Kh = hydrolysis constant = Kw / Ka = 1 x 10-14 / 1.75 x 10-5

= 0.5715 x 10-9 = 5.714 x 10-10

Concentration of Sodium acetate (C) = 0.02 M

Degree of dissociation h =?

Kh= C2h2 / (1-h) C (at Equilibrium) (we neglect (1-h) term due very small value.

finally degree of dissociation (h) = square root Of (Kh / C)

= square root Of (5.714 x 10-10 / 0.02)

= square root Of (285. 7 x 10-10)

= square root Of (2.86 x 10-8) = 1.691 x 10-4

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