In mice, the following alleles were used in a cross: W = waltzing gait w = nonwa

Question

In mice, the following alleles were used in a cross:

W = waltzing gait w = nonwaltzing gait

G = normal gray color g = albino

B = bent tail b = straight tail

In a three-point testcross, a waltzing, gray, bent-tailed mouse heterozygous for all three genes is crossed to a nonwaltzing, albino, straight-tailed mouse, and the following progeny obtained:

waltzing gray bent 48

waltzing albino bent 63

nonwaltzing gray straight 57

nonwaltzing albino straight 66

waltzing gray straight 12

waltzing albino straight 15

nonwaltzing gray bent 15

nonwaltzing albino bent 18

A) Use Chi-square analyses to determine which of the three genes show evidence of linkage.

B) For any genes that show linkage, calculate their genetic distance.

Explanation / Answer

Waltzing +bent + albino which is equal 48+63+15+18 isequal to 144

non waltizing + straight + gery which is equal to 12+15+57+64 is equal to 150

total offsprings 294

144/294+150/294*294 which is equal to 0.48+0.51*294 equal to 291.06 .

chisquare analyses ; [observed -excepted ]2 / expected equal to 294-291/294 equal to 1.73/294 equal to 0.005 .

so form this we get know that walting ,straight and albino are showing a little evidence

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