0. 5. Sodium carbonate is a reagent that may be used to standardize acids in the

Question

0. 5. Sodium carbonate is a reagent that may be used to standardize acids in the same way you used KHP in this experiment. In such a standardization, it was found that a 0.512 g sample of sodium carbonate required 25.3 mL of a sulfuric acid solution to reach the end point for the reaction. Na2CO3(aq) + H2SO4(aq) H2O(l) + CO2(g) + Na2S04 (aq) What is the molarity of the H2S04? 6. A solution contains 6.30x10A-2 g of oxalic acid, H2C204.2H20, in 250mL. What is the molarity of this s = 0 . 000S mo 002 M

Explanation / Answer

Q5

m = 0.512 g of Na2CO3 requires

V = 25.3 mL of H2SO4 solution...

find molarty of acid

mol of Na2CO3 = mass/MW = 0.512 /105.9888 = 0.004831 mol

ratio is 1:1 so

0.004831 mol of acid

[H2SO4] = mol/V = 0.004831/(25.3*10^-3) = 0.19094 M

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