can you please show all your steps. I am lost dure Im the cete andgt EXAMPLE 14.
ID: 579220 • Letter: C
Question
can you please show all your steps. I am lost
Explanation / Answer
Ans 14.4
Balanced equation with ICE table
CO + 2H2 = CH3OH
I 0.75 1 -
C - x - 2x +x
E 0.75 - x 1-2x x
At equilibrium
Partial pressure of CO = 0.295 bar
0.75 - x = 0.295
x = 0.455 bar
At equilibrium
Partial pressure of H2 = 1 - 2x = 1 - 2*0.455 = 0.09 bar
Partial pressure of CH3OH = x = 0.455 bar
Equilibrium constant
Kp = pCH3OH /(pH22 pCO)
= 0.455/(0.09*0.09*0.295)
Kp = 190.416
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