5. Circle the intermolecular force that accounts for the difference in the follo

Question

5. Circle the intermolecular force that accounts for the difference in the following cases (a) The boiling point of hydrogen bromide (HBr) is -66°C but the boiling point of hydrogen fluoride (HF) is 20°C Answer: hydrogen bonding, dipole-dipole interactions, or dispersion forces (b) The boiling point of hydrogen (H) is-253°C but the boiling point of bromine (Br) is 59°C. Answer: hydrogen bonding, dipole-dipole interactions, or dispersion forces (c) The boiling point of ammonia is-33°C but the boiling point of nitrogen trifluoride (NF) is-129°C Answer: hydrogen bonding, dipole-dipole interactions, or dispersion forces (d) The boiling point of tetrabromomethane is 190°C but the boiling point of tetrachloromethane is 77°C. Answer: hydrogen bonding, dipole-dipole interactions, or dispersion forces (e) The boiling point of butanoic acid is 164°C but the boiling point of hexane is 68°C Answer: hydrogen bonding, dipole-dipole interactions, or dispersion forces butanoic acid hexane

Explanation / Answer

a) the boiling point of HF > HBr due to the presence of INTERMOLECULAR HYDROGEN BONDING.

b) As the size increases, the dispersion forces also increase, thus larger Br2 has higher boiling point than smaller H2.

DISPERSION FORCES

C) THE boiling point of Nh3 > that of NF3 due to the INTERMOLECULAR HYDROGEN BONDING IN NH3.

d) the boiling point of CBr4> CCl4 due to the increase in DISPERION FORCESwhich in turn are due to the increase in size of the atoms.

e) butanoic acid has stronger intermolecular Hydrogen bonding compared to hexane which is non-polar.

Thus its boiling point is higher.

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