2. What is the percentage of copper (by weight) in copper(II) sulfate pentahydra

Question

2.What is the percentage of copper (by weight) in copper(II) sulfate pentahydrate, CuSO4•5H2O?

a. What is the percentage of Cu in the sample?

b.What is the formula weight of the compound?

4.A student is given 1.525 g of pure CuO. To recover the Cu present in the compound, the dark powdery solid was dissolved in 15.0 mL of 6M HCl, the solution diluted with 50.0 mL of water, and 0.40 g of Mg was added. Was this enough Mg to displace all the Cu2+ ions from the solution?

a.If there is not enough Mg present, how much more Mg metal would be needed (minimum)?

b.If there was enough Mg to displace the Cu, how much 6 M HCl (in mL) would be required to decompose the excess Mg present?

3.A student is given 1.6604 g of an unknown copper compound. Following the isolation by displacement by Mg, 0.7193 g of Cu metal is recovered.   

a. What is the percentage of Cu in the sample?

b.What is the formula weight of the compound?

4.A student is given 1.525 g of pure CuO. To recover the Cu present in the compound, the dark powdery solid was dissolved in 15.0 mL of 6M HCl, the solution diluted with 50.0 mL of water, and 0.40 g of Mg was added. Was this enough Mg to displace all the Cu2+ ions from the solution?

a.If there is not enough Mg present, how much more Mg metal would be needed (minimum)?

b.If there was enough Mg to displace the Cu, how much 6 M HCl (in mL) would be required to decompose the excess Mg present?

Explanation / Answer

Solution-2) the percentage of copper (by weight) in copper(II) sulfate pentahydrate can be found as-

CuSO4·5H2O = 249.6861 g/mol
Cu = (63.5463 g Cu/mol)
(63.5463) / (249.6861) = 0.254505 = 25.4505% Cu

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