the following reaction has an equilibrium constant,kc, equal to, 3.07x10^-4 at 2
ID: 578122 • Letter: T
Question
the following reaction has an equilibrium constant,kc, equal to, 3.07x10^-4 at 24 c the following reaction has an equilibrium constant,kc, equal to, 3.07x10^-4 at 24 c the following reaction has an equilibrium constant,kc, equal to, 3.07x10^-4 at 24 c 4) The following reaction has an equilibrium constant, Kc, equal to 3.07 x 10 at 24c 2 NOBr (g) 2NO (g) + Br2 (g) For each of the following reaction mixtures, decide whether the reaction is at which direction it will shift to reach equilibrium a) [NOB 0.0720 M, [NO)-0.0 162 M, [Br21-0.0123 M b) [NOBr] = 0.121 M, [NOF 0.0159 M, [Br! = 0.0139 M c) NOBr] = 0.103 M, NO]= 0.0 134 M, [Br21-0.0 181 M d) NOBr] = 0.0472 M, [NO]= 0.0121 M, [Br2-0.0105 M 5) lodine and bromine react to give iodine monobromide, IBr 12 (g) + Br2 (g)(21Br The equilibrium constant, Kc, for this reaction at 150°C is 1.2 x 10. What is the equilibrium constant for t following equation 6) The equilibrium constant for the reaction 2H2 (g) + CO (g) CH3OH (g) is 1.6 x 10° at a certain temperature. If there are 1.17 x 10-2 moles of H2 and 3.46 x 103 moles of CH,OH at equilibrium in a 5.60 L flask, how many moles of CO are present at equilibrium? 7) Predict the sign on AS for the following processes and explain your answer a) C2H2 (g) + 2H2 (g) C2H6 (g) b) GH2 (g) + 3O2 (g) 4CO (g) + 2H20 (g) c) 2C (s) + O2 (g) 2CO (g) d) 2NaHC03 (s) Na2CO3 (s) + H2O (g) + CO2 (g)Explanation / Answer
4)
a)
Qc = [NO]^2 [Br2] / [NOBr]^2
= (0.0162)^2 * (0.0123) / (0.0720)^2
= 6.23*10^-4
Since this is greater than Kc, equilibrium will shift to left
b)
Qc = [NO]^2 [Br2] / [NOBr]^2
= (0.0159)^2 * (0.0139) / (0.121)^2
= 2.40*10^-4
Since this is less than Kc, equilibrium will shift to right
c)
Qc = [NO]^2 [Br2] / [NOBr]^2
= (0.0134)^2 * (0.0181) / (0.103)^2
= 3.07*10^-4
Since this is equal to Kc, reaction is at equilibrium
d)
Qc = [NO]^2 [Br2] / [NOBr]^2
= (0.0121)^2 * (0.0105) / (0.0472)^2
= 6.90*10^-4
Since this is greater than Kc, equilibrium will shift to left
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