i. When ethanol is oxidized to ethanoic acid by heating with acidified potassium

Question

i. When ethanol is oxidized to ethanoic acid by heating with acidified potassium dichromate: a. The ethanol is reduced and the color changes from orange to green b. The ethanol is reduced and the color changes from green to orange. c. The ethanol is oxidized and the color changes from green to orange. d. The ethanol is oxidized and the color changes from orange to green. 2. When ethanol is partially oxidized by an acidified solution of potassium dichromate (VI), the product that can be obtained by distillation as soon as it is formed is: a. Ethanal b. Ethane which compound is converted to butanal by acidified potassium dichromate (VI) solution? a. Butan-1-ol b. Butan-2-ol c. ethanoic acid d. ethane-1,2-diol 3. c. butanone d. butanoic acid 4. Which alcohol cannot be oxidized by an acidified solution of potassium dichromate (VI)? a. (CHs) COH c. (CH3)2CHCH2OH d. CH3CHOHCH2CH 5. An organic compound is prepared from ethanol by a four-step synthesis. Each step gives : yield of 70%, what will be the yield of the organic compound based on the initial amount of th alcohol? a. b. 24% 28% c. 34% d.7096 When 2-iodopropane (CH3CHICH3) is warmed with aqueous potassium hydroxide the major organic product is: 6. c. CH3CH2CH20H d. CH3CH(OH)CH3 a. CH3COCH3 When propan-1-ol is burnt in air, how many molecules of oxygen are consumed for each molecule of propanol? 7. . Propan-1-ol can be oxidized to propanoic acid in the same way as ethanol to ethanoic acid. a. What reagents would you use for this oxidation? b. How would you expect the product to react with sodium carbonate?

Explanation / Answer

1.

(d) The ethanol is oxidised and the color changes from orange to green.

2.

When primary alcohol undergoes partial oxidation in the presence of acidified potassium permanganate forms aldehyde as the product.

So, (a) Ethanal

3.

(a) Butan-1-ol

4.

Tertiary alcohols can not be oxidised by KMnO4

(a) (CH3)3COH

5.

Let us consider intial amount be 100 g.

After first step - 100 * 70 / 100 = 70 g.

After second step - 70 * 70 / 100 = 49 g.

After third step - 49 * 70 / 100 = 34.3 g.

After fourth step - 34.3 * 70 / 100 = 24.01 g.

(a)

6.

CH3CHICH3 + aq. KOH -----------> CH3CH(OH)CH3 + KI

(d)

7.

CH3CH2CH2OH + (9/2) O2 -----------> 3 CO2 + 4 H2O

SO, for each mole of propanol-1 = 9/2 mol of Oxygen is needed.

8.

(a) Acidified potassium permanganate

(b) Actually alcohols donot react with sodium carbonate.

But if they react,

CH3CH2CH2OH + Na2CO3 --------> CH3CH2CH2ONa + CO2 + H2O

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