rank the following molecules from least soluble (1) to most (4) soluble in benze

Question

rank the following molecules from least soluble (1) to most (4) soluble in benzene 8&9 please 7. Rank the following molecules from lowest (1) to highest (3) boiling poin 8. Rank the following molecules from least soluble (1) to most (4) soluble in benzene (CsHe) explain your rankings. OH OH 9. Which of the following molecules will be MOST soluble in water? Briefly describe why you that molecule: 0. Show how the following molecules could hydrogen-bond with water. Which molecule i soluble in water? NH2 HO HO OH O NH2

Explanation / Answer

For solubility there is only one principle to remember - like dissolves like

8) benzene is a non-polar solvent. Hence the molecule that will be most non polar will be most soluble. Your order for the given molecules is

Cyclohexane (1) since it is completely non polar

Cyclohexanol (2) i.e, your last molecule bcz it has a longer non polar segment than the polar part (OH)

cyclobutanol (3) i.e, your second number molecule. It has a shorter non polar segment then cyclohexanol

Ethanol (4) because of the polar OH part

9)aldehydes and ketones are both polar molecules due to the presence of C=O double bond. However among the two, i would say ketone is more polar since aldehyde still has one H atom. So among the given molecules

Butan-2-one (1) most soluble since it is a ketone and has the least number of carbons in the h/c chain

Butaraldehyde(2) since it also has less than 6 carbon atoms in the h/c chain

Pentane-2-one (3) since it has a longer hydrocarbon chain which comes in the way of dissolving.

Note: Aldehydes and ketones with less than 6 carbon chain are more soluble in water due to smaller non polar part.

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