Mary Academy Bay View Determination of the Equivalent Mass of an Acid Pre-Study

Question

Mary Academy Bay View Determination of the Equivalent Mass of an Acid Pre-Study AP Chemistry Equation: used 0.42 f .108 M Nan mrtio: A a. How many meles of OH' are used? solid ac end point. The sudent motes O" b. How many moles of H' trom HCI? moles H c. How many moles of H" are there in the solid acid? #moles of H., in solid acid " # moles of OH', in NaOH . . moles H" inHCl sole. #moles of H., in solid acid-Maowson. Mis in 1000 1000 d. What is the equivalent mass of the unknown acid? Equivalent Mass - moles (15 points)

Explanation / Answer

For the given unknown acid

a. moles of OH- used = molarity x volume

                                   = 0.1085 M x 33.66 ml = 3.65211 mmol

b. moles H+ from HCl used = 0.1049 M x 0.42 ml

                                            = 0.044058 mmol

c. moles H+ in acid = 3.65211 - 0.044058

                               = 3.608052 mmol

d. grams of acid = 0.2349 g

Equivalent mass = 0.2349 g/3.608052 x 10^-3 mol

                           = 65.104 g/mol

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