The E 71% Part 2 (1 point) See Hint Quinine, which was first isolated in 1820 fr

Question

The E 71% Part 2 (1 point) See Hint Quinine, which was first isolated in 1820 from the bark of the cinchona tree, has been used for hundreds of years to treat malaría An elemental analysis of quirine shows that itontains 7399%C7S06H862%Nand 989% O by mass. The first step in determining the empirical formula of the compound is to corvert these masses to moles. To do this you Choose one Assume that we have 1000 g of the compound and treat the percentages as masses 0 Assume that these are equal to the number of moles of each element present. O Reduce these percentages to the lowest ratio of whole numbers Part 3 (4 points) see Hint The next step is to calculate the number of moles of each element present in 100.0 g of compound. Enter your answers below, giving each number of moles to four significant digits mol C mol H mol N mol o Dart 4 (1 noint K1418> VIEW SOLUTION O Type here to search

Explanation / Answer

Element       percent composition     Atomic mass     no of moles
C                  73.99                12             73.99/12 = 6.165
H                   7.5                  1              7.5/1    = 7.500
N                   8.62                14              8.62/14 = 0.6157
O                   9.89                16              9.89/16 = 0.6181

no of moles of C                     H               N                   O
               6.165                7.500            0.6157              0.6181
               6.165/0.6157 = 10    7.5/0.6157 = 12   0.6157/0.6157 = 1   0.6181/0.6157 = 1
The empirical formula = C10H12NO

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