d) Ba(OH)2 (Kjt HsPo.em) Type of reaction e) Mg +Fe(NO)h Type of reaction Type o

Question

d) Ba(OH)2 (Kjt HsPo.em) Type of reaction e) Mg +Fe(NO)h Type of reaction Type of reaction 8) Ca ()+ H2SO4() Type of reaction AgNOs n) + NaBr ) Type of reaction h) Aqueous solution of potassium sulfate is mixed with aqueous solution of sodium chloride. (i) Type of reaction ) Aqueous solution of calcium hydroxide is mixed with acetic acid. Type of reaction Which one of the following will produce highest number of CI ions? (a) 10 molecules of NaCL, (b) 6 molecules of MgCla, (c) 5 molecules of AICl. 7 (d) 12 molecules of KCI. 8 Which of the following will ionize completely in water? (a) CH COOH, (b) NH3, (c) HCL, (d) CH OH, (e) NaCI, () MgCla (8) CH

Explanation / Answer

6. d) 3Ba(OH)2 (aq) + 2H3PO4 (aq) ---> Ba3(PO4)2 (aq) +6H2O (l)

This is a double displacement reaction.(acid-base neutralisation)

e) 3Mg(s) + 2Fe(NO3)3(aq) ---> 2Fe(s) + 3Mg(NO3)2 (aq)

This is a  single displacement (substitution) reaction.

f) Na2CO3(aq) + 2HCl(aq) ---> 2NaCl(aq) + H2O(l) + CO2(g)

This is a decomposition reaction.

g) Ca(s) +H2SO4(aq) ----> CaSO4(s) + H2(g)

This is a single displacement (substitution) reaction.

h)  AgNO3(aq) + NaBr(aq) --> AgBr(s) + NaNO3(aq)

This is a double displacement reaction.

i) K2SO4(aq) + 2NaCl(aq) ---> Na2SO4(aq) + 2KCl (aq)

This is a double displacement reaction.

j) Ca(OH)2(aq) +2 CH3COOH (aq) ----> (CH3COO)2Ca (aq)+ 2H2O (l)

This is a double displacement reaction ( acid-base neutralisation).

8) The ionic compounds will ionize completely in water.

c) HCl will ionize completely in water as H+ and Cl-

HCl(aq)------H2O-----> H+(aq) + Cl-(aq)

e) NaCl will ionize completely in water as Na+ and Cl-

NaCl(aq) ----H2O----> Na+(aq) + Cl-(aq)

f) MgCl2 will ionize completely in water as Mg2+ and Cl-

MgCl2(aq) ----(H2O)----> Mg2+(aq) + 2Cl-(aq)

7. a) 10 molecules of NaCl

NaCl ---> Na+ + Cl-

There is one mole of Cl- present.

So, number of Cl- in one NaCl= 1 mole * 6.022 x 1023 ions/mole = 6.022 x 1023 ions.

In 10 molecules of NaCl = 10 *6.022 x1023 ions = 60.22 x 1023 ions = 6.022 x 1024 ions

b) 6 molecules of MgCl2

MgCl2 ---> Mg2+ + 2Cl-

2 mole of Cl- present

Number of Cl- ions in one MgCl2 = 2 mole * 6.022 x 1023 ions /mole = 12.044 x 1023 ions

So. in 6 molecules MgCl2 = 6 x 12.044 x 1023 ions = 72.264 x 1023 ions = 7.2264 x 1024 ions.

c) 5 molecules of AlCl3

AlCl3 ---> Al3+ + 3 Cl-

Number of Cl- ions in one AlCl3 = 3 mole x 6.022 x 1023 ions/mole = 18.066 x 1023 ions

So, in 5 molecules AlCl3 = 5 x 18.066 x 1023 ions = 9.033 x 1024 ions.

d)12 molecules of KCl

KCl ---> K+ + Cl-

Number of Cl- ions in one KCl = 1 mole x 6.022 x 1023 ions/mole = 6.022 x 1023 ions

So, in 12 molecules KCl= 12 x 6.022 x 1023 ions = 7.2264 x 1024 ions.

Therefore, c) 5 molecules of AlCl3 will ahve the highest number of Cl- ions (9.033 x 1024 ions)

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