a) The following autosomal RFLP genotype frequencies were found in a sample of p

Question

a) The following autosomal RFLP genotype frequencies were found in a sample of people from Thailand:

Gene 1
3.7-kb homozygotes 0.16
2.9-/3.7-kb heterozygotes 0.48
2.9-kb homozygotes 0.36
Gene 2
4.1-kb homozygotes 0.32
4.1-/3.4-kb heterozygotes 0.24
3.4-kb homozygotes 0.44

What are the allele frequencies at each locus?
Gene 1
f(3.7-kb allele) =
f(2.9-kb allele) =
Gene 2
f(4.1-kb allele) =
f(3.4-kb allele) =

b) What would be the genotype frequencies at each locus at Hardy-Weinberf equilibrium? THe Hardy-Weinberg frequencies would be

Gene 1

3.7 homozygotes=

heterozygotes=

2.9 homozygotes=

Gene 2

4.1 homozygotes=

heterozygotes

3.4 homozygotes=

c) What are some of the reasons why one locus can be at Hardy-Weinberg equilibrium, whereas an independent locus in the same population may not?

Explanation / Answer

1a) f (3.7kb allele ) = q2 = (0.16)

q = 0.4

f (2.9 kb allele) = p2 = 0.36 or p = 0.6 (1 - 0.4 = 0.6)

gene 2) f (4.1kb allele) = q2 = 0.32 or q = 0.57

f(3.4 kb allele) = p2 = 0.44 or p = 0.667

b) frequency of 3.7kb allele at Hardy-weinberg equilibrium = 0.4 x 0.4 = 0.16

frequency of 2.9kb allele at Hardy-weinberg equilibrium = 0.6 x 0.6 = 0.36

gene 2)

frequency of 4.1kb allele at Hardy-weinberg equilibrium = 0.57 x 0.57 = 0.32

frequency of 3.4b allele at Hardy-weinberg equilibrium = 0.667 x 0.667 = 0.44

c) allele frequencies at a locus can be in at Hardy - weinberg equilibrium when they undergo random mating in an interbreeding population. Some alleles at a locus violate Hardy - weinberg equilibrium because of migration, mutation, geneflow and gnetic drift.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.