the position versus time for a certain particle the position versus time for a c
ID: 575050 • Letter: T
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the position versus time for a certain particle the position versus time for a certain particle the position versus time for a certain particle 122-Chem 2018-B 8 #2 KQuestion 9 (of 12) 9 2.00 points Assistance A 3.40 g sample of water is injected into an evacuated percentage of water will be vapor when the system reaches equilibrium? Assume ideal behavior of water vapor and that the volume of liquid water is negligible. The vapor pressure of water at 50.0 C is 92.5 mmllg Percent eBook & Reso #2-Go- OVOExplanation / Answer
moles of water vapor can be calculated from gas law, PV= nRT
P= partial pressure of water vapor= vapor pressure at saturation = 92.5 mm Hg, 760 mm Hg= 1 atm
P= 92.5/760 atm =0.122 atm, V= volume in L= 5.5L and T = temperature in K= 50 deg.c= 50+273=323K
R= 0.0821 L.atm/mole.K, n= no of moles = PV/RT= 0.122*5.5/(0.0821*323)= 0.025 moles of water vapor
mass of water vapor =moles of water vapor* molar mass =0.025*18= 0.45 gm
% of vapor=100* mass of water vapor/ total sample mass =100*0.45/3.4= 13.23%
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