Homework #2 1. Calculate the molality of the solution: 8.66 grams of benzene (CH

Question

Homework #2 1. Calculate the molality of the solution: 8.66 grams of benzene (CH6) dissolved in 23.6 gram of carbon tetrachloride 2. Calculate the vapor pressure of water above a solution prepared by adding 22.5 grams of lactose (C11H2201) to 200.0 g of water at 338 K. (Vapor-pressure data for water are given in Appendix B) 3. What is the osmotic pressure formed by dissolving 44.2 mg of aspirin (C9He O4) in 0.358 L of water at 25c? 4. A solution containing 0.150 g of Lysozyme enzyme in 210 ml of solution has an osmotic pressure of 0.605 atm at 25 ‰Assuming the organic compound is a nonelectrolyte, what is its molar mass?

Explanation / Answer

Ans 1 :

Number of moles of benzene = given mass / molar mass

= 8.66 / 78.11

= 0.11 mol

Molality = no. of mol of benzene / mass of CCl4 in kg

so putting all the values we get :

= 0.11 / 0.0236

= 4.66 m

So the molality of the solution will be 4.66 m

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