This is the reaction for ozone formation in the stratosphere: 3 O2 (g) <--> 2 O3

Question

This is the reaction for ozone formation in the stratosphere:

3 O2 (g) <--> 2 O3 (g)

and the energy (reaction coordinate) diagram for the process.

Based on this information, select all of the following that are correct:

Question 4 options:

Entropy favors the products because the product molecule is more massive and complex than the reactant molecule.

The process is reactant favored due to entropy.

More energy goes into this process than is released.

The process is reactant favored because 286 kJ/mol of energy is released upon formation of ozone.

Entropy favors the products because the product molecule is more massive and complex than the reactant molecule.

The process is reactant favored due to entropy.

More energy goes into this process than is released.

The process is reactant favored because 286 kJ/mol of energy is released upon formation of ozone.

Question 4 (2 points) E,t E, = 498.5 kJ/mol 2 03 rxn 286 kJ/mol 3 O2 Reaction Coordinate

Explanation / Answer

the correct answers are options 2,3.

2. since there are 3 molecules of oxygen at the reactant side and 2 ozone at the product side so entropy(randomness) will decrease. and we know that every reaction wants entropy to increase. so the process is reactant favoured.

3. since we are giving 498 kj and getting 286. so true.

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