BASE with Sl Base Trial #1 | Acid (NaOH)vol base / nal 25622.50 mass acid Value

Question

BASE with Sl Base Trial #1 | Acid (NaOH)vol base / nal 25622.50 mass acid Value gramsml Initial Value gras . 3.28 0.00 mL Mass or2 Volume 2 Used Base RATIO: (NaOH)vol base / Trial #2 | Acid 1.85 45,5mass acid grams 2.56 22.50 mL Initial Value Mass or Volume Used rams 13. What is the percentage difference between the two calculated ratios for trials 1 and 2? a) 0.45 % b) 1.2 % c) 2.4 % d)3.5 % 14. Based on the answer to question #21, should this student run a third trial for Part I? a) Yes b) No c) More information is needed

Explanation / Answer

Part I

Trial #1

mass of acid = 0.72 g

vol of base = 22.50 ml

mass acid/vol base = 0.72 g/22.50 ml = 0.032 g/ml

Trial #2

mass of acid = 0.71 g

vol of base = 23 ml

mass acid/vol base = 0.71 g/23 ml = 0.031 g/ml

13. percentage difference between the two trials

(d) 3.5%

14. /based on the answer, should the student run a third trial for part I,

b) No

The values are within the accetable error range and no third trial is thus needed.

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