QUESTION 6 The next five problems are calculational in nature. The initial probl

Question

QUESTION 6 The next five problems are calculational in nature. The initial problem statement in each case is simlar but the numbers will be difterent In several cases, you have more information than you need Be sure to answer only the question asked in each case - don't get camed away It is found in an attempt to determine the mass percentage of sodium hypochlonte that 13 85 ml of 0 191 M thiosulfate are required to reach the endpoint in the itration of 1.97 g of bleach sample. How many moles of thiosulfate ion were delivered? Include units of mol with your answer and report it to at least five decimal places QUESTION 7 our d in an attempt to determine the ma percentage of sodium, hypochlone that 13 34 mL of 0 192 M thiosulfate are equi ed to reach the er port in the titration of 2.16 g of bleach sample How many moles of triodide ion must have been in the solution being analyzed? Include units of imol with your answer and report it to at least five decimal places QUESTION 8 It is found in an attempt to determine the mass percentage of sodium hypochlorite that 12 64 ml of 0 192 M thiosulfate are required to reach the endpoint in the brration of 2 .31 g of bleach sample How many moles of hypochionte ion must have been in the solution being analyzed? include units of mol with your answer and report it to at least five decimal places QUESTION 9 It is found in an attempt to determine the mass percentage of sodium hypochlorite that 12 23 ml. of 0 192 M thiosulfate are required to reach the endpoint in the titration of 2 19 g of bleach sample. How many moles of sodium hypochlonite must have been in the solution being analyzed? Incluade units of mol with your answer and report it to at least five decimal places

Explanation / Answer

6. molarity of thiosulfate = 0.191 M

Volume of thiosulfate added = 13.85 ml = 0.01385 L

moles of thiosulfate delivered = molarity x volume

                                                = 0.191 M x 0.01385 L

                                                = 0.00264 mol

7. moles of thiosulfate delivered = molarity x volume

                                                    = 0.192 M x 0.1334 L

                                                    = 0.00256 mole

moles of triiodide present = 0.00256 mole/2 = 0.00128 mol

8. moles of thiosulfate delivered = 0.192 M x 0.001264 L

                                                    = 0.00243 mole

moles of hypochlorite present in sample = 0.00243 mole/2 = 0.001215 mol

9. moles of thiosulfate delivered = 0.192 M x 0.001223 L

                                                    = 0.00235 mole

moles of hypochlorite present in sample = 0.00235 mole/2 = 0.001175 mol

10. moles of thiosulfate delivered = 0.192 M x 0.001406 L

                                                    = 0.0027 mole

moles of hypochlorite present in sample = 0.0027 mole/2 = 0.00135 mol

mass of NaOCl in sample = 0.00135 mol x 74.44 g/mol = 0.1005 g

mass percentage sodium hypochlorite in bleach sample = 0.1005 g x 100/2.27 g = 4.43%

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