Determining the Density of Liquid and Solid Substances 1. You have calculated th

Question

Determining the Density of Liquid and Solid Substances 1. You have calculated the density of the unknown metal in g/ml. To det identity you have used a reference table where the densities are given in g/em. Explain why you could do that. ermine its 2. Ice is less dense than liquid water at the same temperature. At O'C the density of ice is 0.9167 g/cm3 and the density of liquid water at 0'C is 09998 g/mL. .Consider two samples: one of water and one of ice. Both samples have the same mass of 492 Number of sig figs in 492 Number of sig figs in 0.9167: Calculate the volume of both samples and round off your answers to the correct numbers Volume of a 492 g sample of water Volume of a 492 g sample of ice Show all your work below. Which formula do you need to use to calculate the volume? Density-Volume Mass = Density × Volume Volume - Density Mass Mass 3. Use your volume calculations from question 2 and answer the following. A 500-mL bottle with 492 mL of liquid water in it was placed in a freezer. Will the ice fit into the bottle after the water freezes? Explain your answer

Explanation / Answer

1) The two units are practically the same. This is due to the fact that we have the following relationship:

1 mL = 1 cm3

Hence, the densities expressed in g/mL and g/cm3 are the same.

2) Number of sig. figs. in 492 = 3

Number of sig. figs in 0.9167 = 5

Volume of a 492 g sample of water = (mass of water)/(density of water) = (492 g)/(0.9999 g/mL) = 492.0984 mL 492.10 mL (correct to 5 sig. figs).

Volume of a 492 g sample of ice = (mass of ice)/(density of ice) = (492 g)/(0.9167 g/mL) = 536.7077 mL 536.71 mL (ans).

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