I am having trouble finding the specific heat capacity. Help would really be app

Question

I am having trouble finding the specific heat capacity. Help would really be appreciated.

Part C A mass of 48.5 g of an unknown solid initially at 100.0 ° C is added to an ideal constant pressure calorimeter containing 100.0 g of water (Cs,water 4.184J/(g.° C) initially at 20.0 °C. After the mixture reaches thermal equilibrium, the final temperature is recorded to be 38.86 specific heat capacity of the unknown solid? C. What is the Express your answer to three significant figures. View Available Hint(s) g.CC

Explanation / Answer

qsolid = mass of solid x specific heat x temp change

qsolid = 48.5 x Cs x (38.86 - 100)

qsolid = -2965.29 Cs

now

qwater = mass of water x specific heat of water x temp change

qwater = 100 x 4.184 x ( 38.86 - 20)

qwater = 7891.024

now

since no heat is lost

qsolid + qwater = 0

-2965.29 Cs + 7891.024 = 0

Cs = 7891.024 / 2965.29

Cs = 2.66 J/ g C

so

the specific heat capacity of the unknown solid is 2.66 J/ g C

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