2.) When the following equation is balanced properly under acidic conditions, wh

Question

2.) When the following equation is balanced properly under acidic conditions, what are the coefficients of the species shown?

Hg2+ + Cu+ = Hg + Cu2+

Water appears in the balanced equation as a (reactant, product, neither) ____________? with a coefficient of ____________?. (Enter 0 for neither.)

How many electrons are transferred in this reaction? __________?

3.) When the following equation is balanced properly under acidic conditions, what are the coefficients of the species shown?

Cu + NO3- = Cu2+ + NO

Water appears in the balanced equation as a (reactant, product, neither) ____________? with a coefficient of ____________?. (Enter 0 for neither.)

How many electrons are transferred in this reaction? __________?

4.)When the following equation is balanced properly under acidic conditions, what are the coefficients of the species shown?

ClO3- + Br- = Cl- + BrO3-

Water appears in the balanced equation as a (reactant, product, neither) ____________? with a coefficient of ____________?. (Enter 0 for neither.)

Which element is reduced?__________?

5.) When the following skeletal equation is balanced under acidic conditions, what are the coefficients of the species shown?

SO42- + Cr3+ = H2SO3 + Cr2O72-

Water appears in the balanced equation as a (reactant, product, neither) ____________? with a coefficient of ____________?. (Enter 0 for neither.)

Which species is the reducing agent_______________?

6.) When the following skeletal equation is balanced under acidic conditions, what are the coefficients of the species shown?

Cr3+ + Co = Cr2+ + Co2+

Water appears in the balanced equation as a (reactant, product, neither) ____________? with a coefficient of ____________?. (Enter 0 for neither.)

Which species is the oxidizing agent_______________?

Explanation / Answer

2.

Hg2+ + 2 Cu+ = Hg + 2 Cu2+

Neither and 0

2 electrons

3.

(i)

Oxidation Half reaction          Reduction Half reaction

Cu ---> Cu2+                 NO3- ------------> NO

(ii)

Balance all other atoms than H and O

Cu ---> Cu2+                 NO3- ------------> NO

(iv)

To balance O in acidic medium add H2O molecules.

Cu ---> Cu2+                 NO3- ------------> NO + 2 H2O

(v)

To balance H in acidic medium add H+ ions.

Cu ---> Cu2+                 NO3- + 4 H+ ------------> NO + 2 H2O

(vi)

To balance charges add electrons at more positive charge side.

Cu ---> Cu2+ + 2 e                  NO3- + 4 H+ + 3 e ------------> NO + 2 H2O

(vii)

To balance electrons in both half reactions,

do OHR * 3 and RHR * 2

3 Cu ---> 3 Cu2+ + 6 e                  2 NO3- + 8 H+ + 6 e ------------> 2 NO + 4 H2O

(vii)

Add both half reactions to get final balanced redox reaction.

3 Cu + 2 NO3- + 8 H+ ------------->3 Cu2+ +2 NO + 4 H2O

SO,

Water apears as product with coefficient 4

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.