Question is in first paragraph. please also give a worded explanation on how you

Question

Question is in first paragraph. please also give a worded explanation on how you got your answer.

Solution B: You will now use some of the 0.10 M H,So, solution just made to prepare 100 mL of a solution that is 0.10 M H2SO, and 0.27 M KIO3. You will use solid KIOs for the solute and the 0.10 M H SO solution as the solvent. How many grams of KIOs are needed to prepare this solution? Show your calculations on the report sheet. Since this is not simply a measure and mix type of solution, follow the procedure below. Weigh out the calculated amount of solid KIO3 in a 100 mL beaker. Add about (5ThL of the 0.10 M H2S04 solution. Gently warm this mixture on a hot plate to dissolve the solid. Do not overheat and avoid boiling. Swirl the beaker occasionally to hasten dissolving. When the solid has dissolved, transfer the solution into a 100 mL volumetric flask using a funnel. Rinse out the beaker with two 10 mL portions of 0.10 M H,SO4 solution. Add these rinsings to the volumetric flask through the funnel also. Carefully add enough additional 0.10 M H,SO, solution to fill the volumetric flask to the mark. With the stopper in the flask, invert and swirl several to thoroughly mix the solution.

Explanation / Answer

Volume of Solution to be prepared = 100 mL

Molarity of solvent H2SO4 = 0.1 M

Molarity of solute KIO3 = 0.27 M

Moles of solute = Molarity of solute x Volume of solution in lit.

Moles of solute = 0.27 x (100/1000)

Moles of solute = 0.027

Mass of solute = Moles of solute x Molar mass of solute

Mass of solute = 0.027 x 214

Mass of solute = 5.778 g

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