1. Write the expression for the equilibrium constant (the equilibrium equation)

Question

1. Write the expression for the equilibrium constant (the equilibrium equation) for each of the following chemical reactions. (FE exam manual) 2) 3) 4) Bao(s) + CO2(g) BaCO3(s) C(s) + CO2(g) CO(g) 2. H2PO, is in equilibrium with HPO in water: H2PO4 T = 25°C; [H2PO4 ] = 9.698 x 10-5 M: [H+] = [HPO42-] = 3.018 x 10-6 M Using the extended Debye-Huckel approximation equation, calculate the following: 1) when = 0 a) the activity coefficients for H2PO4, HPO2, and H b) the equilibrium constant, Ka2 c) the equilibrium constant corrected for ionic strength, Ka2 d) pKa2 and pKa2 2) when = 0.01 a) the activity coefficients for H2PO4, HPO2, and H b) the equilibrium constant, Ka,2 c) the equilibrium constant corrected for ionic strength, Ka2 d) pKa2 and pKa2e key H,PO -log KapKa2

Explanation / Answer

1)

for equilibrium constant only gaseous and liquid substances will contribute. and ratio of concentration (or partial pressure) of products to the reactants

so for the first reaction

Keq = PNO2 * PCl2 / PNOCl2

second reaction

Keq = 1/  PCO2  

third reaction

Keq = [H3O+] [NO3-] / [H2O] [HNO3]

fourth reaction

Keq = PCO /  PCO2  

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