Rx K2S#04 516 mg assessment/take/take jsp course assessment id 19856 1course jd

Question

Rx K2S#04 516 mg assessment/take/take jsp course assessment id 19856 1course jd 24520 1&content; id 670962 18iquestion num 7x 08tog Take Test: Homework_Lecture 4_Chapter 12 Test Information Multiple Attempts This test allows 3 attempts This is attempt number 1 Force Complation This test can be saved and resumed later w Question Completion Status: Moving toanother question wil save this respons. Question 7 of 10 Question 7 1 points Save Caloium citrate (CalCeHisO3lz m.w 498) solution contains 32.5 grams of calcium citrate per f.oz. of solution. Express the ditrate concentration in mEqjml a.662 mEqml b. 13.24 mEqm c.65.26 mEqml. Chapber 20 Practi ppts ch 4 5 6 7 8 9

Explanation / Answer

Ans d) 4.41 mEq/mL

1 oz = 29.5735 mL

Number of moles of calcium citrate = given mass / molar mass

= 32.5 / 498

= 0.06526 mol

Each mole has double the concentration of citrate , so eq of citrate = 2 x 0.06526

= 0.1305 eq

concentration = equivalents / volume of solution

= 0.1305 / 29.5735

= 0.00441 Eq/mL

or 4.41 mEq/mL

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