C Chapter 14 Homework 1 Introduction to Integrated Rate Laws 9 of 10 Learning Go

Question

C Chapter 14 Homework 1 Introduction to Integrated Rate Laws 9 of 10 Learning Goal: To understand how to use integrated rate laws to solve Part A A starts at mle marker 145 on a highway and drives at 55 mi/hr in the direction of decreasing marker numbers. What mile marker will the car reach after 2 The rate constant for a certain eaction is A 5.30x 10sit the initial neactant concentration was 0 900 f, what will the concentration be ather 5.00 minutes Express your answer with the appropriate units View Available Hints) calcuialting how far This problem can easily be solved by the car traviels and subtracting that distance rom the starting maker of 145 55 mi/hr 2 hr = 1 10 miles traveled milemarker 145-110 miles milemarker 35 were to wrte aformula forthis calculation, w" mi Value Units t as follows Figure 1of2 : Part B A zero-onder reaction has a constant rate of 3.40x10* M/s. Ifaher 40 0 seconds the concentration has dropped to 5.00M10-2 M,wh Express your answer with the appropriate units 1 View Available Hintis Value Units

Explanation / Answer

Answer:

Part-A:

rate constant (K) = 5.30 x 10-3 sec

Initial concentration (a) = 0.9 M

Time (t) = 5 minutes = 5 x 60 sec = 300 sec

We know for the First order reaction

K = (2.303 / t) log a / (a-X) a= Initial concentration

X = concentration of products

(a-X) = remaining concentration of the reactants.

5.30 x 10-3 = (2.303 / 300) log 0.9 / (a-X)

(0.0053 x 300) / 2.303 = log 0.9 / (a-X)

1.59 / 2.303 = log 0.9 / (a-X)

0.690 = log 0.9 / (a-X)

log 0.9 / (a-X) = 0.690

0.9 / (a-X) = log-10.693

0.9 / (a-X) = 4.93

0.9 / 4.93 = (a-X)

(a-X) = 0.182 M

Hence the remaining concentration after 5 minutes = 0.182 M.

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