Please help with all portions of the problems below. Thank You for you help! - I

Question

Please help with all portions of the problems below. Thank You for you help!

- Ideal Specific Gravity The specific gravity of water at 20°C is about 0.9982; the specific gravity of methanol at 20°C is about 0.7917. Assuming volume additivity of the components, estimate the specific gravity of the mixture at 20°C. SG = What volume of this mixture is required to provide 350.0 mol of methanol? liters SHOW HINT LINK TO TEXT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Attempts: O of 5 used SAVE FOR LATER SUBMIT - Actial Specific Gravity Repeat part (a) with the additional information that the specific gravity of the mixture at 20°C is 0.9345 (making it unnecessary to assume volume additivity)- What is the real volume of the mixture required to provide 350.0 mol methanol? liters What percentage error results from the volume-additivity assumption?

Explanation / Answer

a)

Specific gravity = dsubstance/dreference ( d = density)

   = m

substance/m

reference (m = mass; at constant volume)

volume additivity mean the volume of the solution is equal to the sum of the volumes of its ingredients).

Assume 1 mL of water and 1 mlL of methanol

Mass of H2o = 0.9982 gram at 20 C

Mass of MeOH = 0.7917 gram at 20 C

Spcificgravity at 20 C = Mass of H2o/Mass of MeOH

                                   = 0.7917/0.9982

                                 SG = 0.7933

350 mol of methanol = 11214 gram of methanol (350*32.04) 32.04 is molecular weight

Volume of methanol = mass/density = 11214/0.7933 = 14135.8 mL or 14.135 liter

Initially we assumed the volume ratio is 1:1 so

14.135+14.135 = 28.27 liter of mixture having 350 mol of methanol

b)

350 mol of methanol = 11214 gram of methanol (350*32.04) 32.04 is molecular weight

Volume of methanol = mass/density = 11214/0.9345 = 12000 mL or 12 liter

Initially we assumed the volume ratio is 1:1 so

12+12 = 24 liter of mixture having 350 mol of methanol

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