The membrane protein bacteriorhodpsin, which contains seven transmembrane alpha

Question

The membrane protein bacteriorhodpsin, which contains seven transmembrane alpha helices, was attached by its N-terminal to a glass slide, and the C-terminal chemically linked to a magnetic force microscope. The microscope tip was then pulled away from the slide. As it withdraws, & helices pull out of the membrane, two at a time, as shown in the figure, giving a force-extension curve with four 'teeth'. If the force required to extract the first pair of alpha helices in the example above is given by (f/pN) = 20(x/nm) +(x/nm)^2, up to an extension of 10 nm. what is the work needed to extract the first pair of helices? Express your answer to two significant figures and include the appropriate units. What would be the work in J needed to extract 1 mol of pairs of helices? omega = Express your answer to two significant figures and include the appropriate units. omega =

Explanation / Answer

Part A: Given that

First pair of helices (x) = 2

Extension = 10 nm

Insert the values in the formula

(f/pN) = 20(x/nm) +(x/nm)2

= 20 (2/10) + (2/10) 2

=101/25

= 4.04 J

Part B:

1 mole = 6.02214×1023 particles

But 1 Joule per mole = 1 Joule/ 6.02214×1023 = 1.66054 x 10^-24

Insert the values in the below formula

(f/pN) = 20(x/nm) +(x/nm)2

= 20(2 *1.66054*10^-24/10)+(2/10)^2

= 0.04 J

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