3. For reaction as indicated: Kp = 4.36 x 10-2 (at some T) N204 (g) 2 NO2(g), (a

Question

3. For reaction as indicated: Kp = 4.36 x 10-2 (at some T) N204 (g) 2 NO2(g), (a) Find K when the equation is written as: 2 NO2(g) N2O4(g) Kp = (b) Find K for the equation as: 2 N2O4(g) 4 NO2 (g) 4. For each reaction, how will the change shift the equilibrium and what will be the effects on the [...] and n values? Equation for reaction Change Shift Applied (R, L, or N) (I, D, or s) Effects NH4C1(s) NH3(g) HCl (g) add NH3 [NH3] [HC1] + = nNH4C1(s) = NH4C1 (s) NH3 (g) + HCI (g) add HCl [HCl] nNH4CI (s) = [NH3 ] = [HCl] nNH4C1 (s) = [NH3] = NH4Cl (s) NH3(g) + HCI (g) add NH4C1 =

Explanation / Answer

3)
Given reaction is:
N2O4 (g) <—> 2 NO2 (g)
Kp1 = p(NO2)^2 / p(N2O4) = 4.36*10^-2

a)
the reaction now is:
2 NO2 (g) <—> N2O4 (g)
Kp = p(N2O4) / p(NO2)^2
= 1/kP1
= 1/(4.36*10^-2)
= 22.9
Answer: 22.9

b)
the reaction now is:
2 N2O4 (g) <—> 4 NO2 (g)
Kp = p(NO2)^4 / p(N2O4)^2
= (Kp1)^2
= (4.36*10^-2)^2
= 1.90*10^-3
Answer: 1.90*10^-3

I am allowed to answer only 1 question at a time

Related Questions

Navigate

• Browse (All)
• Browse 3
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.