finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet say

Question

finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the cabinet is used to store A chemist working as a safety inspector glycerol, tetrahydrofuran, pentane, acetone, and methyl acetate. Data Sheets (MSDS), the chemist finds the following information: 1.3 g em to known densities. First, from her collection of Material Safety lidu n ri the density and comparing to known densities.Fist, from her collecton of Material Safety plans to try to identify the unknown liquid by measuring liquid glycerol Sres casos thr density tetrahydrofuran 0.89 gem pentane 0.63gcm 0.79 gem3 acetone methyl acetate 0.93 gem Next, the chemist measures the volume of the unknown liquld as 1,357 L and the mass of the unknown liquid as 850. g. Calculate the density of the liquid. Round your answer to 3 significant digits. Given the data above, is it possible to identify the liquid? yes no lycerol pentane acetone methyl acetate If it is possible to identify the tiquid, do so. Explanation Check

Explanation / Answer

Answer:-

Mass of unkown liquid = 850 g

volume of unkown liquid = 1.357 L

we know that 1 L = 1000 cm3

So, volume of unkown liquid = 1.357 x 1000 cm3

= 1357 cm3

So, density of unkown liquid = mass / volume

= 850/1357

= 0.626 g.cm-3

Yes , it is possible to identify the liquid.

The liquid is identified as = pentane

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