× G Chegg, The Student Hul Homework chapter 4 ×/owLv2 | Online teachin × nment/t

Question

× G Chegg, The Student Hul Homework chapter 4 ×/owLv2 | Online teachin × nment/takeCovalentActivity.do?locator: assignment-take& takeAssignmentSession Locator= as Refe Use the References to access important values if neede [Review Topics] For the following reaction, 0.326 moles of iron are mixed with 0.117 moles of chlorine gas iron(s) + chlorine(g) iron (III) chloride(s) What is the formula for the limiting reagent? What is the maximum amount of iron(III) chloride that can be produced? moles Submit Answer Retry Entire Group 9 more group attempts remaining

Explanation / Answer

The balanced reaction will be

2Fe(s) + 3Cl2(g) ------- 2FeCl3(s)

2 moles of Fe requires 3 moles of Cl2 gas

Since number of moles of Fe (0.326) > number of moles of Cl2 (0.117)

Hence Cl2 gas is the limiting reagent

Formula for the limiting reagent = Cl2 (g)

Number of moles of FeCl3 formed = 2/3 * Number of moles of Cl2 = 2/3 * 0.117 = 0.078 moles

Hence the answer will be 0.078 moles

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