In a reaction involving the iodination of acetone, the following volumes were us

Question

In a reaction involving the iodination of acetone, the following volumes were used to make up the reaction mixture: 15 mL 4.0 M acetone + 15 mL 1.0 M HCl + 15 mL 0.0050 M I2, + 20.0 mL water.

please show all the work

3. Reaction Rate: The lodination of Acetone Name Section Post Lab Questions: Answer question on this sheet. Show all work. 1. In a reaction involving the iodination of acetone, the following reaction mixture was used: 15mL 4.0 M acetone, 15.00 mL 1.0 M HCI, 15.00 mL 0.0050 M 12, and 20.0 mL water. a. What was the molarity of the acetone, HCl and I, in the reaction mixture? (Recall that b. The color of the above reaction mixture disappeared in 450 seconds. What was the rate of the reaction? (Hint: First determine the initial concentration of the iodine.)

Explanation / Answer

a.) molarity of acetone = 15 x 4 = M x 65

M = 0.923 M

molarity of HCL = 15 x 1 = M x 65

M = 0.231 M

molarity of I2 = 15 x 0.0050 = M x 65

M = 0.0012 M

b.) Moles of I2 = concentration x volume

= 0.0050 x 0.015 = 7.5 x 10-5 mol

Total volume of solution = 15 + 15 + 15 + 20 = 65 mL = 0.065 L

[I2]0 = moles/volume = 7.5 x 10-5/0.065 = 0.00115 M

Rate = [I2]0 /t = 0.00115/450 = 2.56 x 10-6 M/s

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