The following data represents the sex - linked gene in cats where the female cat
ID: 56819 • Letter: T
Question
The following data represents the sex - linked gene in cats where the female cats may be yellow or black (both homozygous states) and where the heterozygous state is calico. The males will be either yellow or black:
Phenotypes
Yellow
Calico
black
Females
152
88
8
Males
188
56
a.What is the frequency of the yellow and black alleles in the females in this population?
b) What is the frequency of the yellow and back alleles in the males in this population?
c) What is the frequency of the yellow and black alleles in the combined data of males and females in this population?
d) What is the frequency of the yellow and black alleles in the next generation among the females if we assume the Hardy Weinberg equilibrium?
e) What is the frequency of the yellow and black alleles in the next generation among the males if we assume the Hardy Weinberg equilibrium?
Yellow
Calico
black
Females
152
88
8
Males
188
56
Explanation / Answer
Total number of female = 248
Total number of males = 244.
a) The recombination frequency of yellow in female = No of recombinant frequency/total number of population X 100
= 152/248 X 100 = 61.2%
Frequency of black in female = 8/248 x 100 = 3.2
b) The recombinant frequency of yellow in male = 188/244 x 100= 77%
Frequency of black in male = 56/244 X 100 = 22.9%
C) Frequency of yellow and black in combined data =
yellow = (152+188)/(248+244) X 100 = 340/ 492 X 100 = 69.1%
Black = (8+56)/492 = 13%
d) Based on the data the yellow p = 0.61 q = 0.032
The frequency of yellow = p X p = 0.37
The frequency of black = qxq = 0.001.
e) frequency of yellow and black in males
Yellow = pxp = 0.77 x0.77 = 0.59
Black = qxq = 0.22 x 0.22 = 0.04
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