emistry.uoguelph.ca/ogi-bi rker.exe?us-2MDTALBacap PART 2- H2SO4 Titrations volu
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emistry.uoguelph.ca/ogi-bi rker.exe?us-2MDTALBacap PART 2- H2SO4 Titrations volume of H2SO4 Make sure to get this number correct and use it correctly - it is important. 2500 mL Unknown Number 1076 First Determination Burette Final Volume 2758 mL Burette Initial Volume 5.55 mL Volume NaoH 2203 mL how a complete calculation of how2 NaOH+Hso,-Na So4+2 H2o ou calculated the number of moles of NaoH used in the first titration. Total number of moles of NaoH used in the first titration. Week 6 Density-De-..pdf ^ BIOL1070.W18-10..pdf ·Explanation / Answer
From the statement i understand that you have 0.05 M of H2SO4, you took 25 ml of this (0.025 lliters)
moles of acid = molarity * volume = 0.05 * 0.025 = 0.00125 moles of available acid
the neutralization reaction is
2 NaOH + H2SO4 ====== Na2SO4 + 2 H2O
you need 2 moles of naoh for every mole of acid if you have 0.00125 moles of acid then you need
2 * 0.00125 = 0.0025 moles of base required
you required 22.03 ml or 0.02203 Literrs
Molarity of NaOH = moles / volume = 0.0025 / 0.02203 = 0.11348 M
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