iPad 16:25 a bblearniri-c.edu *100%- QUESTION 9 2 pointsSave Answer If the heat

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iPad 16:25 a bblearniri-c.edu *100%- QUESTION 9 2 pointsSave Answer If the heat of fusion for water is 80 cal/gram, how many calories are needed to melt 45 grams of ice at 0° C? Path: p words:0 QUESTION 10 3 points Save Answer Bromine (Br2) has a freezing point of (-7° C) and a boiling point of (60° C. at each temperature. Indicate the state occurring .30° c? 2. 70° C? 3. (-15° C) Click Save and Subumit to save and submit. Click Save All Ansvers to save all answers. Save All Answers Save and Submit

Explanation / Answer

9. Heat of fusion of water = 80 cal/g

calories needed to melt 45 g ice at 0 oC would be,

= 45 g x 80 cal/g

= 3600 cal

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10. Bromine (Br2) has,

melting point = -7 oC

boiling point = 60 oC

State of bromine thus at the given temperatures would be,

1. 30 oC : Liquid

2. 70 oC : Vapor

3. -15 oC : Solid

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