Equation (1) Subsequently, the copper(I) nitrate will be converted into solid co
ID: 566259 • Letter: E
Question
Equation (1) Subsequently, the copper(I) nitrate will be converted into solid copper(ll) hydroxide, Cu(OH)2 (Equa- Cu(s) + 4 HNOg(aq) Cu(NO3)2(aq) + 2 H2O() + 2 NO2(g) tion 2), which, in tun, is converted through heating into solid copper(II) oxide, CuO (Equation 3). Equation (2) Equation (3) Next, the copper ions will be brought back into solution by converting copper() oxide into Cu(NO3)2(aq) + 2 NaOH(aq) Cu(OH2)(s) + 2 NaNO3(aq) Cu(OH)2(s) + heat CuO(s) + H2O(g) copper(Il) sulfate, CuSO4 (Equation 4). Equation (4) Cu0(s) + H2SOdaq) Cuso,(aq) + H2O(/)Explanation / Answer
Equation (1): Here, initially Cu had 0 oxidation state. But in it's nitrate, it got oxidised and possess +2 oxidation state. All nitrogens initially had +5 oxidation state. After the reaction, some got reduced to +4 oxidation as in NO2. Therefore, this is a redox reaction.
Equation (2): Here, the ions got displaced as initially there were copper nitrate and sodium hydroxide, which later formed copper hydroxide and sodium nitrate. This is an example for double displacement reaction as ions are displaced.
Equation (3): The compound cipper hydroxide had been broken down. Therefore, it is a decomposition reaction.
Equation (4): The base copper oxide reacts with sulfuric acid to form copper sulfate (salt) and water. This is an acid - base reaction which forms salt and water. Therefore it is neutralization reaction.
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