Moles of S 2 O 8 -2 consumed .000000 .000100 .000200 .000300 .000400 .000500 Rea

Question

Moles of S2O8-2 consumed

.000000

.000100

.000200

.000300

.000400

.000500

Reaction #1

Cumulative

Time (s)

000.0

188.4

360.6

554.4

783.0

993.0

Examine the data showing the times of appearance of color for solution 1 (first row on data sheet). Compare the size of the first interval with the size of the last interval for solution 1. Are the time intervals constant, increasing, or decreasing? How should they be changing and why? (Ignore the slight change in solution volume that occurs).

Moles of S2O8-2 consumed

.000000

.000100

.000200

.000300

.000400

.000500

Reaction #1

Cumulative

Time (s)

000.0

188.4

360.6

554.4

783.0

993.0

Explanation / Answer

time required for first interval = 188.4 s

time required for last interval = 993.0 - 783.0 = 210 s

so, time interval is increasing.

so, the value of rate is changed from first interval to last interval. [as rate = change in concentration / change in time]

but, for a particular set of kinetic reaction, rate should be same through out the process. Therefore, time interval will remain same for equal change in concentration.

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