Please complete the table below and show your work on a separate sheet of paper.
ID: 564380 • Letter: P
Question
Please complete the table below and show your work on a separate sheet of paper. Note that the stock solution of BSA is 2.0 mg/ml, Final (uL) 100 ul. Tube Volume Volume of Final BSA Amount of 2.0mg/mL BSA Volume Concentration BSA in 100 (ug/mL) stock (HL) dH2O 100 ul of stock | 2.000 ug/mL 200 Hg of stock | 100 . | 1.500 ug/mL | 1.000 ug/mL | 750 ug/mL | 500 ug/mL 250 ug/mL | 125ug/mL | 25 ug/mL | 100 ul. ul. of stock | 100 ul. of stock | 100 ul. ul. of stock of stock | 100 .of stock | 100. of stock | 100 ul.Explanation / Answer
Given,
concentration of stock BSA solution = 2.0 mg/ml = 2,000 ug/ml
1 ml = 1000 uL
So,
Tube B
Volume of BSA stock = 1,500 ug/ml x 100 uL/2,000 ug/ml = 75 uL
BSA in 100 uL = 150 ug
Tube C
Volume of BSA stock = 1,000 ug/ml x 100 uL/2,000 ug/ml = 50 uL
BSA in 100 uL = 100 ug
Tube D
Volume of BSA stock = 750 ug/ml x 100 uL/2,000 ug/ml = 37.5 uL
BSA in 100 uL = 75 ug
Tube E
Volume of BSA stock = 500 ug/ml x 100 uL/2,000 ug/ml = 25 uL
BSA in 100 uL = 50 ug
Tube F
Volume of BSA stock = 250 ug/ml x 100 uL/2,000 ug/ml = 12.5 uL
BSA in 100 uL = 25 ug
Tube G
Volume of BSA stock = 125 ug/ml x 100 uL/2,000 ug/ml = 6.25 uL
BSA in 100 uL = 12.5 ug
Tube H
Volume of BSA stock = 25 ug/ml x 100 uL/2,000 ug/ml = 1.25 uL
BSA in 100 uL = 2.5 ug
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.