How do I How do I digtal No Backups for 26a Connect to a 02/11/18 68% 1st attemp

Question

How do I How do I digtal No Backups for 26a Connect to a 02/11/18 68% 1st attempt Part 1 (0.3 point) Jid See Periodic Table See H A chemist wishes to make a solution using 4.41 g of CoCla in which the total concentration of CI ions is equal to 0.233 mol/L What must the final volume of the solution be? Let's start by understanding the relationship between [CoCh] and [Cr]. In order for [CI-1 to equal 0.233 M what must (CoClal equal? See Hint Part 2 (0.3 point) Molarity is definels seluc so we need to calculate the moles of CoCls How many moles of CoCly are equivalent to L. solution 17 OF 23 QUESTIONS COMPLETED

Explanation / Answer

mass of CoCl3 = 4.41 grams

molar mass of CoCl3 = 165.28 gram/mole

Concentration of Total Cl- = 0.233 mole/L

Molarity = mass of solute/molar mass of solute x1000/volum in ml

volume in ml = mass of solute/molarmass of solute x1000/concentration

               = 4.41/165.28 x1000/0.233 = 114.51

Volume of solution = 114.51 mL

CoCl3------------ Co+3 + 3 Cl-

[Cl-] = 0.233 mole/L

Concentration of CoCl3= 0.233/3= 0.07767 moles/L

Part-2.

Molarity of CoCl3= 0.07767 moles/L

Volume = 114.51 ml= 0.11452 L

Molarity = number of moles/volume in L

Number of moles = Molarity x volume in L

                           = 0.07767 x 0.11452= 0.0089 moles

number of moles of CoCl3= 0.0089 moles.

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