9) The density (in g/em\') of a gold nugget that has a volume of 1.68 cmn\' and

Question

9) The density (in g/em') of a gold nugget that has a volume of 1.68 cmn' and a mass of 32.4 gis A) 0.0519 B) 19.3 C) 54.4 D) 0.0184 E) 324 10) The density of silver is 10.5 g/cm. A piece of silver with a mass of 61.3 g would occupy a volume of A)0.171 B) 644 C) 10.5 D) 0.00155 E) 5.84 cm3 11) The number 0.00430 has A) 2 B) 3 C)5 D) 6 significant figures. 12) The number 1.00430 A)2 B) 3 C)s D) 6 E) 4 has significant figures. 13) The correct answer (reported to the proper number of significant figures) to the following is 6.3 x 3.25·- A) 20. B) 20.475 C) 20.48 D) 20.5 E) 21 14) The correct result (indicating the proper number of signiflcant figures) of the following addition is 12 0.12 +0012 A) 13 B) 13.3 C) 13.33 D) 13.332 E) none of the above (0.002843)( 12.80184) 0.00032 15) A) 113.73635 B) 113.736 C) 113.74 D) 113.7 E) 1.1 x 10

Explanation / Answer

Ans 9

Volume = 1.68 cm3

Mass = 32.4 g

Density = mass/volume

= 32.4/1.68 = 19.285 = 19.3 g/cm3

Option B is the correct answer

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