1. NaCl is 58.5 g/mole. How many grams do I need to make 25 mL of a 0.3 M soluti

Question

1. NaCl is 58.5 g/mole. How many grams do I need to make 25 mL of a 0.3 M solution? If have a 3 % solution of NaCl, how many mL do I need to make 20 mL of a .3% solution? How many mL of water would I have to add? Given the following: 1% = 1g/100mL, MW = grams/ mole. You have 175 ml of a 5% NaCl stock solution (Mw = 58.44g/mol). You used it all and need to make 275 ml more. How much NaCl would you need to weigh out? Show your work and report in grams. 3. Given the following: 1% = 1g/100mL, Mw = grams / mole, FW compound. How much of a 2 M glucose stock solution and how much water are needed to prepare 350 ml of a 0.4 M glucose solution? Show your work. 4. formula/molecular weight of a

Explanation / Answer

Ans 1 :

Molarity = no. of moles of solute / volume of solution in L

0.3 = n / 0.025

n = 0.0075 mol

So the mass of NaCl required = 0.0075 x 58.5

= 0.439 grams

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