ONLv2/ Online teaching and I × eAssignment/takeCovalentActivity.doPlocator-assig
ID: 561031 • Letter: O
Question
ONLv2/ Online teaching and I × eAssignment/takeCovalentActivity.doPlocator-assignment-take&take;ÄssignmentSessionLocator-assig Use the References to access important values If needed for this question. 1. How many ATOM IS of carbon are present in 1.84 moles of carbon tetrachloride ? atoms of carbon. 2. How many MOLES of chlorine are present in 5.95x1022 molecules of carbon tetrachloride ? moles of chlorine. Submit Answer Retry Entire Group 3 more group attempts remaining 2req s 2req Previous how Hlint 15 MacBook ProExplanation / Answer
(1)Number of moles of CCl4 (Carbon Tetra Chloride) = 1.84 mole
Number of molecules = Number of moles * Avogadro’s number = 1.84 * 6.023 * 10^23 molecules
Since number of carbon atoms in CCl4 is 1 , Hence number of Carbon atoms present = 1*1.84 * 6.023 * 10^23 = 11.082 * 10^23
(2)Number of molecules of CCl4 = 5.95 * 10^22
Number of moles of CCl4 = (5.95 * 10^22) / (6.023 * 10^23) = 0.0988 mole
Since number of Cl atoms in CCl4 is 4, hence number of moles of Cl present = 4 * 0.0988 mole = 0.3952 mole
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