Unknown No Trial I Trial 2 1. Mass of metal (e) Temperature of metal (boiling wa

Question

Unknown No Trial I Trial 2 1. Mass of metal (e) Temperature of metal (boiling water) (C) 3. Mass of calorimeter (e) 4 Mass of calorimeter + water (g) S. Mass of water (g) 11.180 20.55 19.131 19 23 SC & Temperature of water in calorimeter C 19 7. Maximum temperature of metal and water from graph C) 8. Instructor's approval of graph Calculations for Specific Heat of a Metal Temperature change of water, AT c) 2. Heat gained by waterJ) a Temperature change of metal,A7eC) a. Specific heat of metal, equation 25.5 (Ug·°C) 5. Average specific heat of metal (J/g·°C) Data A how calculations for Trial 1 using the correct number of significant figures.

Explanation / Answer

Ans. Trial 1:

#1. dT, water = (31.5 – 19.0)0C = 12.50C

#2. Heat gained by water is given by-

q = m s dT                            - equation 1

Where,

q = heat gained

m = mass

s = specific heat

dT = Final temperature – Initial temperature

Putting the values in equation 1-

q1 = 20.881 g x (4.184 J g-10C-1) x 12.50C = 1092.0763 J

#4. dT, metal = (88.0 – 31.5.0)0C = 56.50C

#5. Total heat lost by metal = Total heat gained by water = 1092.0763 J

Let the specific heat of metal be s1.

Putting the values in equation 1-

            1092.0763 J = 69.305 g x s1 x 56.50C

            Or, s1 = 1092.0763 J / 3915.7325 g 0C

            Hence, s1 = 0.2789 J g-10C-1

#Trial 2:

#1. dT, water = (27.5 – 19.0)0C = 8.50C

#2. Putting the values in equation 1-

q1 = 19.127 g x (4.184 J g-10C-1) x 8.50C = 680.232628 J

#4. dT, metal = (88.0 – 27.5)0C = 60.50C

#5. Total heat lost by metal = Total heat gained by water = 680.232628 J

Let the specific heat of metal be s2.

Putting the values in equation 1-

            680.232628 J = 69.326 g x s2 x 60.50C

            Or, s2 = 680.232628 J / 4194.223 g 0C

            Hence, s2 = 0.1622 J g-10C

#5. Now, average specific heat of metal = (s1 + s2) / 2

                                    = (0.2789 J g-10C + 0.1622 J g-10C) /2

                                    = 0.2206 J g-10C

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