(20%) The following is the balanced deaction with respect to Ha equation for the

Question

(20%) The following is the balanced deaction with respect to Ha equation for the formation of ammonia, and rate of N2(g) + 3H2 (g) -2NH3(g). [H21 Rate a. What is the rate of reaction with respect to N2? b. What is the rate of reaction with respect to NH3? 2) (20%) Given the following balanced equation, determine the rate of to[NO]. If the rate of NO loss is 4.84 × 10-2 M/swhat is the rate of loss of C27 reaction with respect 2 NO(g) + Cl2(g) 2 NOCl(g) a) 4.84 x 10-2 M/s b) 2.42 x 10-2 M/s c)1.45 10-1 MIs d) 9.68 10-2 Ms 3) (20%) Given the following rate law, how does the rate of reaction change if the concentration of Y is tripled? Rate k[XIIYI a) The rate of reaction will increase by a factor of 3. b) The rate of reaction will increase by a factor of 6. c) The rate of reaction will decrease by a factor of 3. d) The rate of reaction will increase by a factor of 9. 4) (20%) Which of the following statements are False? where the a) The rate constant does not depend on the activation energy for a reaction b) A catalyst raises the activation energy of a reaction. c) Rate constants are temperature dependent. d) The addition of a homogeneous catalyst does not change the activation energy of a products are lower in energy than the reactants. given reaction. 5) (2096) Which rate law is unimolecular? c) rate = k [A][B][C][D] b) rate k [] ) extra credit (10%) For a 1st order reaction, how many half-lives are required for the a) rate k [AIB oncentration of reactant to decrease to 1/8th of its original value?

Explanation / Answer

Q1

a)

the rate of N2, reactant, must include negative sign --> Rate = -d[N2]/dt

b)

for NH3, it is a product, so use positive

Rate = 1/2*d[NH3]/dt

Q2

if

[NO] losses = 4.84*10^-2 then

raito is 1:2 so

[Cl2] = 1/2*[NO] = 1/2*4.84*10^-2 = 2.42*10^-2 M/s

Q3

if we triple y, then

3^2 =9x effect on rate

choose D

Q4

a. true

b is false, it will lower it

c. true

d. true

Q5

unimolecular -- > implies 1 molecule

so only B will do

Q6

1/8 = 12.5

1 half life = 50%

2 half lives = 25

3 half lives = 12.5

therefore, we nede 3 half lives

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