, crit810CH12 So5dX Olis1O-Chapter 17 × CHI810-Chapter17 × Gilbert 4thCH1957 m/c
ID: 560218 • Letter: #
Question
, crit810CH12 So5dX Olis1O-Chapter 17 × CHI810-Chapter17 × Gilbert 4thCH1957 m/courses/wp-content/uploads/2017/11/CH1810-Pr-Ex-3-Fa2017-copy pdf c prof katz cnm + Automat Pb2+(aq) + Cu(s) Pb(s) + Cu2+(aq) 2. Calculate the cell potential for the following reaction that takes place in an electrochemical cell at 25°C Sn(s) I Sn2+(aq, 0.022 M) Il Agt(aq, 2.7 M) 1 Ag(s) 3. What mass of aluminum can be plated onto an object in 755 minutes at 5.80 A of current? 4. Aluminum crystallizes in a face centered cubic structure with an edge length of 2/2 rExplanation / Answer
2) Nernest equation,
cell reaction = Sn(s) + 2Ag^+(aq) ----> Sn^2+(aq) + 2Ag(s)
Ecell = E0cell - 0.0591/nlog[Sn^2+]/[Ag^+]^2
E0cell = E0cathode - E0anode
= 0.8 - (-0.13)
= 0.93 v
Ecell = 0.93 - (0.0591/2)log(0.022/2.7^2)
= 1 V
3)
faradays first law
equivalent weight of Al (Ewt)= atwt / charge = 27/3 = 9 g/equiv
W = Zit
Z= E/F
w = E/Fit
F = faraday = 96500 C
i = current = 5.8 A
t = time = 755 min = 755*60 = 45300 sec
w = weight of Al deposited = (9/96500)*5.8*45300 = 24.5 g
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