lonization of ionic compounds, coefficients, and ionic equations Soluble ionic c
ID: 560196 • Letter: L
Question
lonization of ionic compounds, coefficients, and ionic equations Soluble ionic compounds exist as individual ions in solution. Therefore, ionic equations show individual ions rather than their corresponding aqueous compounds However, any solid, liquid, and gaseous chemical species will still be depicted as a molecule or ionic compound in an ionic equation, such as the precipitate of a precipitation reaction. Starting with the balanced molecular equation, you will use the coefficients and subscripts to determine the coefficients for all of the ions in the balanced complete ionic equation. For example, if a molecular equation indicated two formula units of calcium nitrate as shown below: 2Ca(NOs)2(aq) then it would be represented in a complete ionic equation as follows 2Ca2+(aq) +4NO3 (aq) This is because we multiply the coefficient preceding the molecule by the subscripts that apply to each ion of the molecule. In ionic equations, you may include or omit the phase for ions (aq) because ions can only exist in the aqueous state in water. However, you should always indicate the phases for molecules (solid, liquid, or gas) in ionic equations. Part C Complete ionic equation 2NaOH (aq) + Zn(NO3)2 (aq) Zn(OH), (s) + 2NaNO3 (aq) The molecular equation you determined in Part B is shown above for your convenience. Examine each of the chemical species involved to determine the ions that Be sure to consider both the coefficients and subscripts of the molecular equation, and then write this precipitation reaction in the form of a balanced complete ionic equation Express your answer as a chemical equation including phases. Type an underscore ) or a carat (A) to add subscripts and superscripts more quickly HintsExplanation / Answer
Given reaction is 2NaOH(aq) + Zn(NO3)2(aq) –------------ Zn(OH)2(aq) + 2 NaNO3(aq)
So the Complete ionic equation is
2Na+ (aq) +2 OH- (aq) + Zn2+ (aq) + 2NO3- (aq)--------->Zn2+(S) + 2 OH- (s) + 2Na+ + 2NO3-
Zn(OH)2 is slightly soluble in water.
So the net ionic equation will be
Zn2+ + 2(OH)- -------- Zn(OH)2
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