Use the VSEPR model to determine the electron-domain geometries of carbon tetrac

Question

Use the VSEPR model to determine the electron-domain geometries of carbon tetrachloride (CCl4), carbon disulfide (CS2), and ammonia (NH3).

Carbon tetrachloride (CCl4): (pick one)

a. linear

b. trigonal planar    

c. tetrahedral

d. trigonal bipyramidal

e. octahedral

Carbon disulfide (CS2): (pick one)

a. linear

b. trigonal planar    

c. tetrahedral

d. trigonal bipyramidal

e. octahedral

Ammonia (NH3):

a. linear

b. trigonal planar    

c. tetrahedral

d. trigonal bipyramidal

e. octahedral

NBr3, based on the number of electron domains. (pick one)

a. linear

b. trigonal planar    

c. bent

d. tetrahedral

e. trigonal pyramidal

f. trigonal bipyramidal

g. seesaw

h. T-shaped

i. octahedral

j. square pyramidal

k. square planar

KrCl4
geometry: (pick one)

a. linear

b. trigonal planar    

c. bent

d. tetrahedral

e. trigonal pyramidal

f. trigonal bipyramidal

g. seesaw

h. T-shaped

i. octahedral

j. square pyramidal

k. square planar

L. pentagonal bipyramidal

m. pentagonal pyramidal

n. pentagonal planar

bond angle: (pick one)

a. 60°

b. 72°    

c. 90°

d. 109.5°

e. 120°

f. 180°

IO4

geometry: (pick one)

a. linear

b. trigonal planar    

c. bent

d. tetrahedral

e. trigonal pyramidal

f. trigonal bipyramidal

g. seesaw

h. T-shaped

i. octahedral

j. square pyramidal

k. square planar

L. pentagonal bipyramidal

m. pentagonal pyramidal

n. pentagonal planar

bond angle: (pick one)

a. 60°

b. 72°    

c. 90°

d. 109.5°

e. 120°

Explanation / Answer

according to VSEPR electron domain geometries

1. CCl4 has tetrahedral geometry

2. CS2 has linear geometry

3. NH3 has tetrahedral geometry

4. NBr3 has tetrahedral geometry

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