6 The oxidation number of N in NaNOs is D)-3 E) none of these A) +6 B) +5 C) +3

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6 The oxidation number of N in NaNOs is D)-3 E) none of these A) +6 B) +5 C) +3 What volume of a 0.580 M solution of calcium chloride contains 1.28 g of solute? A) 2.21 ml B) 34.2 ml C) 50.3 ml D) 19.9 ml E) 2.22 ml Which of these will occur if solutions of copper(Il) sulfate and barium chlorid are mixed together? A) CuCla will precipitate: Ba*2 and SO2 are spectator ions. 8) CuSOs will precipitate; Ba*2 and Ch are spectator ions. C) BaSO4 will precipitate: Cu*2 and CI are spectator ions D) BaClz will precipitate: Cu*2 and SO42 are spectator ions. E) No precipitate will form. PART II: Problems. Show all appropriate work to earn full credit. 1. Write the molecular, total ionic, and the net ionic equations when solutions of lead(II) nitrate and ammonium sulfate react. Be sure to indicate phases on all reaction (9 points) Molecular Total lonic Net lonic

Explanation / Answer

6)

Oxidation number of Na = +1

Oxidation number of O = -2

lets the oxidation number of N be x

we have below equation to be used:

1* oxidation number (Na) + 3* oxidation number (O) + 1* oxidation number (N) = net charge

1*(+1)+3*(-2)+1* x = 0

-5 + 1 * x = 0

x = 5

So oxidation number of N = +5

Answer: B

7)

Molar mass of CaCl2 = 1*MM(Ca) + 2*MM(Cl)

= 1*40.08 + 2*35.45

= 110.98 g/mol

mass of CaCl2 = 1.28 g

we have below equation to be used:

number of mol of CaCl2,

n = mass of CaCl2/molar mass of CaCl2

=(1.28 g)/(110.98 g/mol)

= 1.153*10^-2 mol

we have below equation to be used:

M = number of mol / volume in L

0.58 = 1.153*10^-2/ volume in L

volume = 0.019886 L

volume = 19.9 mL

Answer: D

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