OWLv21Online teaching an... X Review Topics References Use the References to acc

Question

OWLv21Online teaching an... X Review Topics References Use the References to access important values if needed for this question. The following information is given for ethanol, C2HOH, at 1 atm: 1 pts 2redq Boiling point : 78.4°C Heat of vaporization = 200 cal/g Melting point =-114.5°C Heat of fusion = 26.0 cal/g How many calories of energy are needed to vaporize a 27.9 g sample of liquid ethanol at its normal boiling point of 78.4°C Energy needed- Not Visited cal Submit Answer Retry Entire Group 8 more group attempts remaining

Explanation / Answer

Hvap = 200 cal/g

mass - 27.9 g

we have below equation to be used

Q = mass * Hvap

= 27.9 g * 200 cal/g

= 5580 cal

Answer: 5580 cal

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