Data Mass of S0 ml beaker 20,e121 Mass of 50 mL beaker plus sodium chloride22 35
ID: 559617 • Letter: D
Question
Data Mass of S0 ml beaker 20,e121 Mass of 50 mL beaker plus sodium chloride22 3530 Mass of 150 mL. beaker b b Mass of 150 mL beaker plus silver nitrate o 35 32 Mass of filter paper 12sel Mass of 150 mL beaker plus filter paper plus silver chloride (after Calculations 1. Calculate the mass of silver chloride produced in the reaction. (Show the calculation below.) Percent yield is 2. Calculate the percent yield of silver chloride for the reaction. calculated using the equation % yield-(actual yield/theoretical yield) x 100 where the actual yield is the mass of silver chloride that you got and the theoretical yield is the maximum mass of silver chloride that the reaction could produce from the masses of reactants that were used. The theoretical yield will be given to you at the next lab meeting. (Show the calculation below.)
Explanation / Answer
Q1
mass of AgCl from this reaction
Mass of AgCl = (66.6366) - (66.11758) = 0.51902 g
Q2.
mol of NaCl = mass of NaCl /MW = (30.8330-29.0121)/58.8= 0.030967
mol of AgNO3= mass AgNO3/ MW = (68.8630-66.11758)/169.87 = 0.016161
clearly, Ag is limiting
0.016161 mol of Ag = 0.016161 mol of AgCl
mass = mol*MW = 0.016161*143.3212= 2.3162 g
% yield = real / theoretical * 100% = (0.51902 )/2.3162 *100 = 22.40 %
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